can u please tell me, what is meant with ‘line of intersection’ in question 17 of 2010 paper.
The ‘line of intersection’ is the line where the mirrors touch each other. So, for example, if the mirrors were standing upright the line of intersection would be vertical, and then the incident ray would be in the horizontal plane.
This is my first time seeing an equation for Kepler’s Law. Shouldn’t velocity be inversely proportional to the square of the radius, which can be derived by equating the equations for the centripetal force (force = mass times v^2 over radius) and gravitation?
You can’t apply the equation for centripetal force here because it only applies for circular motion; the comet is not in a circular orbit so that equation isn’t true.
May I ask why sin(theta1) / sin(theta2) = 4/3 ? I can’t see an obvious link
It’s from the equation linking refractive index n to angle of incidence θ: n1 sin θ1 = n2 sin θ2. in this case n1 = 1 and n2 = 4/3.
Hi Lucy, thanks very much for your comment.
This is a really interesting point, and I’m really grateful to you for bringing it up.
I had never before come across the formula refractive index = real depth/apparent depth. There is a reason for that: it’s not generally true. If you look at any derivation of the formula (here’s one example http://saburchill.com/physics/chapters3/0004.html), you will see the phrase “If i and r are small angles” (where i and r are the angles of incidence in air and water). But in general the angles of incidence are not small angles — they are only small angles when you are looking straight down at the fish swimming almost directly beneath you. But, when fishing, if you look straight down you will either see a boat or the bank: the only time you will see a fish directly below you is when you are about to fall into the water, which is not a normal or desirable fishing scenario.
I don’t think the solution I have constructed is incorrect, but do I think that you are right that C is a perfectly good answer. If you consider the case when we are looking directly down then θ1 = θ2 = 0, so cosθ1 = cosθ2 = 1, so we do get the answer 1m, which gives us C.
But if you consider all the other cases, where θ1 > θ2, then cosθ1 < cosθ2, we get an answer of more than 1m, which gives us D.
So, given that this is a multiple choice question, we’ve got a bit of a problem! Ah well, I guess you can take comfort in the fact that there won’t be any multiple choice questions in 2015.
Her assumption is that r1=r2 while your was that the fish were at the same location at different heights
Yes you are absolutely right. And possibly you are supposed to assume that r1=r2 in this question.
But in my answer above I point out that this is only true when the angles of incidence are small, which implies that the fish is directly under your boat (in which case you don’t see it), or if you are standing in the water, the fish is swimming around your legs (and in my experience of angling they don’t do that).
For question 21 isn’t the answer actually C: 1m as refractive index = real depth/apparent depth and 1.33×0.75 = 0.9975? The maths in the solution shown is flawed in the initial set up.
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