Oxford PAT 2011, Question 25

2011_page14

3 thoughts on “Oxford PAT 2011, Question 25

    1. Hi James, thanks for your question.

      I crossed out the ‘smaller’ and replaced with ‘larger’ because I don’t think there is a solution otherwise. The word ‘smaller’ is just an error in the question.

      The question says that, for all the boxes, length/width is a constant (call it L), and height/length is a constant (call it H/L). Then height/width = (height/length)(length/width) = H. So if the widths of the small, medium and large boxes are s, m and l respectively, the volumes are LHs^3, LHm^3 and LHl^3 respectively.

      But if we look at C, we can see that the base area of the small box is Ls^2, and the base area of the large box is Ll^2. But l must be bigger than s, so the base area of the large box must be larger than the base area of the small box, not larger.

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