How did u get equation A?
Wouldnt it be 8ssHsL =mmHmL?
Yes that’s right. But if 8ssHsL = mmHmL then, cancelling out the H and L, we get 8sss = mmm, i.e. 8s³ = m³. So, taking cube roots of both sides, we get 2s = m, or s = m/2.
I see, thanks for the explanation- this site has been very helpful.
Hi, why have you crossed out smaller?
Hi James, thanks for your question.
I crossed out the ‘smaller’ and replaced with ‘larger’ because I don’t think there is a solution otherwise. The word ‘smaller’ is just an error in the question.
The question says that, for all the boxes, length/width is a constant (call it L), and height/length is a constant (call it H/L). Then height/width = (height/length)(length/width) = H. So if the widths of the small, medium and large boxes are s, m and l respectively, the volumes are LHs^3, LHm^3 and LHl^3 respectively.
But if we look at C, we can see that the base area of the small box is Ls^2, and the base area of the large box is Ll^2. But l must be bigger than s, so the base area of the large box must be larger than the base area of the small box, not larger.
Fill in your details below or click an icon to log in:
You are commenting using your WordPress.com account. ( Log Out / Change )
You are commenting using your Twitter account. ( Log Out / Change )
You are commenting using your Facebook account. ( Log Out / Change )
You are commenting using your Google+ account. ( Log Out / Change )
Connecting to %s
Notify me of new comments via email.
Notify me of new posts via email.