Oxford PAT 2013, Question 17

2013_page13

5 thoughts on “Oxford PAT 2013, Question 17

  1. Since a= (Mg-mgsina)/(M+m) and a must be 0 for the masses to be stationary

    Mg-mgsina = 0

    Therefore Mg = mgsina, so M = msina

    Wouldn’t this and the fact that they must be stationary in the first place, and not moving at constant velocity, be necessary for the marks?

    p.s thanks for the great resource that is this website!

    1. Yes that’s right. I guess to be strictly correct the conditions for the mass to be stationary are that its acceleration is zero, and it was not already moving (because if it were it would be moving at a constant speed).

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