Since a= (Mg-mgsina)/(M+m) and a must be 0 for the masses to be stationary
Mg-mgsina = 0
Therefore Mg = mgsina, so M = msina
Wouldn’t this and the fact that they must be stationary in the first place, and not moving at constant velocity, be necessary for the marks?
p.s thanks for the great resource that is this website!
I’m totally sorry I’ve only just seen that this in your solution already!
No worries 🙂
what is the condition for teh mass to be stationary? 0 acceleration and thus at equillibrum?
Yes that’s right. I guess to be strictly correct the conditions for the mass to be stationary are that its acceleration is zero, and it was not already moving (because if it were it would be moving at a constant speed).
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