Oxford PAT 2014

Question 1
Question 2
Question 3
Question 4
Question 5
Question 6
Question 7
Question 8
Question 9
Question 10
Questions 11 and 12
Question 13
Question 14
Question 15
Question 16
Question 17
Question 18
Question 19

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2 thoughts on “Oxford PAT 2014

  1. For question 9, I think it is MUCH easier to just derive the circle’s equation and equate it to the slope of tangent. You get two answers if you take into account both (x)^2 and (-x)^2 are valid in original equation of circle.

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