Oxford PAT 2015, Question 17

2015_paper__page17

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9 thoughts on “Oxford PAT 2015, Question 17

    1. Yes, you are right. I think you get another mark for putting the answer in decimals — it says so on the front of the paper. So I guess you should do so. But of course everyone hates arithmetic :-).

    1. Hi Jemisha, thanks for your question. The value of cos(kx-wt) varies between +1 and -1. So dy/dt varies between -wA and +wA respectively. The question asks for the “maximum vertical velocity”, which is wA.

    1. Yes you are absolutely right; thanks for pointing it out. Somehow I managed to fail to spot the sentence in the question that had all the numbers in it. I have added the bottom three lines to the answer, containing the calculation of the actual value.

    1. Sure, no problem.

      Firstly, we’ve been given an equation for the height y and we are being asked a question about the vertical velocity. The vertical velocity is the differential of the height with respect to time, so it makes sense to differentiate the expression and see what we get.

      When we do this, we can treat the expression kx as a constant. If you don’t know this differential immediately, you can work it out by using the trigonometric identity sin(A-B) = sinA cosB – sinB cosA, and differentiating that expression. You will find that the differential then simplifies, using another trig identity, to -wAcos(kx-wt).

      Then we can observe that we have been asked for the maximum value of the velocity. We know that all cosines vary between -1 and +1, so we can see that the highest possible value is when cos(kx-wt) is -1, so the highest value is wA.

      Is that OK?

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